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PLEASE HELP QUICK!!
Follow the instructions for the problem.
Suppose you are Mr. X working as an assistant engineer at DESCO. One day you tested a transformer of rating 30KVA, 2400/120 V, and 50Hz and found the following data:
Low voltage winding resistance=0.1Ω
Low voltage leakage reactance=0.22 Ω
The high voltage winding resistance=0.035 Ω
High voltage leakage reactance=0.012 Ω

Respuesta :

jayilych4real

R01= 14.1 Ω

R02=  0.03525Ω

Calculations and Parameters

Given:

K= E2/E1 = 120/2400

= 0.5

R1= 0.1 Ω, X1= 0.22Ω

R2= 0.035Ω, X2= 0.012Ω

The equivalence resistance as referred to both primary and secondary,

R01= R1 + R2

= R1 + R2/K2

= 0.1 + (0.035/9(0.05)^2)

= 14.1 Ω

R02= R2 + R1

=R2 + K^2.R1

= 0.035 + (0.05)^2 * 0.1

= 0.03525Ω

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