The surface area S of a right pyramid is given by S=1/2P1+B, where P is the perimeter of the base, 1 is the slant height, and B is the area of the base. Solve for 1

Please help​

Respuesta :

The expression for the slant height is l = 2(S-B)/P

Subject of formula

The subject of formula is a way of representing a variable in  terms of other variables.

Given the formula for calculating the surface area as;

S=1/2Pl + B

We are to find the value of the slant height.

Subtract B from both sides

S - B = 1/2Pl + B - B
S - B = 1/2Pl

Cross multiply

2(S-B) = Pl

Divide both sides by P

2(S-B)/P =Pl/P
2(S-B)/P = l

Swap

l = 2(S-B)/P

Hence the expression for the slant height is l = 2(S-B)/P

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