Two friends, Abdoulaye and Bilquis, had just bought their first cars. The equation y=35.3xy=35.3x represents the number of miles, yy, that Abdoulaye can drive his car for every xx gallons of gas. Bilquis uses 6 gallons of gas to drive 256.8 miles in her car. How many miles less does Abdoulaye's car travel on one gallon of gas than Bilquis's car?

Respuesta :

Thus, we conclude that for 6 gallons of gas, Abdoulaye's car can travel 45 miles more than Bilquis's car.

How many miles less does Abdoulaye's car travel on one gallon of gas than Bilquis's car?

The linear equation represents the number of miles, y,  that Bilquis can drive if he consumes x gallons of gas.

The equation is:

y = 35.3*x

Now, if Abdoulaye uses 6 gallons of gas and he drives 256.8 miles.

If Bilquis uses 6 gallons of gas, he would drive:

y = 35.3*6 = 211.8

The difference is:

256.8 miles - 211.8miles = 45 miles.

Thus, we conclude that for 6 gallons of gas, Abdoulaye's car can travel 45 miles more than Bilquis's car.

If you want to learn more about linear equations:

https://brainly.com/question/1884491

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