Answer:
The value of the "[tex]\texttt{7}[/tex]" in [tex]17.5[/tex] is [tex]100[/tex] times the value of the "[tex]\texttt{7}\![/tex]" in [tex]25.47[/tex].
Step-by-step explanation:
Subtract [tex]7[/tex] from [tex]17.5[/tex] would turn the "[tex]\texttt{7}[/tex]" in [tex]17.5\![/tex] into a "[tex]\texttt{0}[/tex]":
[tex]\begin{array}{ccccc} & 1 & 7 & . & 5 \\ - & & 7 & & \\\cline{1-5}\\[-1em] & 1 & 0 & . & 5 \end{array}[/tex].
Thus, the value of the [tex]\texttt{7}[/tex] is just [tex]7[/tex].
Turning the "[tex]\texttt{7}[/tex]" in [tex]25.47[/tex] into a "[tex]\texttt{0}[/tex]" requires subtracting [tex]0.07[/tex] from that number. Thus, the value of the "[tex]\texttt{7}\![/tex]" in [tex]25.47\![/tex] would be [tex]0.07\![/tex]:
[tex]\begin{array}{cccccc} & 2 & 5 & . & 4 & 7 \\ - & & 0 & . & 0 & 7 \\\cline{1-6}\\[-1em] & 2 & 5 & . & 4 & 0\end{array}[/tex].
Hence, the value of the "[tex]\texttt{7}[/tex]" in [tex]17.5[/tex] is [tex](7 / 0.07) = 100[/tex] times the value of the "[tex]\texttt{7}\![/tex]" in [tex]25.47\![/tex].
