The magnitude of force area under the curve is 15m². The area under the curve notion was utilized to address this problem by calculating the integration method.
Any equation may represent any curve or straight line. The specified trajectory is a straight line in this case.
To begin, create an equation as a function of x that expresses the trajectory. Later, to obtain the area under the curve, integrate the equation within the appropriate limit.
The curve's equation is constant. Hence, the curve is represented by the following equation:
y = f(x) = c
Where c is the constant.
The area under the curve is expressed with proper limits as:
A = [tex]\int\limits^y_x {Y} \, dx[/tex]
Where A = Area under the curve
x = lower limit of the integration and
y = upper limit of the equation.
Step 1 - Equation of the Curve
The equation of the curve is given as:
y = f(x) = c
Where c = 5,
y = f(x) =5
Step 2 - The expression of the area under the curve is given as;
A = [tex]\int\limits^y_x {Y} \, dx[/tex]
Here , let
1 = x, and
4 = y; and
5 - Y
Hence,
A = [tex]\int\limits^4_1 {5} \, dx[/tex]
= 5 x (4-1)
= 5 x 3
A = 15m²
During the limit, the curve's equation remains constant.
The area under the curve may be calculated using the integration technique with the correct limit of the curve's equation.
The force area beneath the curve has a magnitude of 15m².
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