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Find equations of the tangents to the curve x = 6t2 4, y = 4t3 4 that pass through the point (10, 8). (enter your answers as a comma-separated list.)

Respuesta :

The equation of the tangent line will be: y = x - 4

How to compute the equation?

x = 6t² + 4

y =✓4t³ + 2

Point (10,6)

dy/dt = 12t³

dx/dt = 12t

at (10,6)

6t² + 4 = 10 and 6.

The equation of the tangent line will be:

y = 6 + 1(x - 10)

y = 6 + x - 10.

y = x - 4

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