Find an equation of the tangent line to the curve at the point corresponding to the given value of the parameter. x = t cos(t), y = t sin(t); t =

Respuesta :

The equation of the tangent line to the curve at the point corresponds to the given value of the parameter is

[tex]y - 0 = pi(x + pi)[/tex]

This is further explained below.

What is the equation of the tangent line to the curve at the point corresponds to the given value of the parameter?

Generally, the equation for  dx/dt  is  mathematically given as

dx/dt = cost - tsint

dy/dt = sint + tcost

slope at t =[tex]\pi[/tex]

[tex]slope at t = dy/dx = \frac{[sint + tcost ]}{[cost - tsint ]}[/tex]

[tex]= \frac{[0 - pi]}{[-1] = pi}[/tex]

Given that

[tex]t = \pi,\\ x = -\pi,\\ y = 0[/tex]

[tex]y - 0 = pi(x + pi)[/tex]

In conclusion, The equation of the tangent line to the curve at the point that corresponds to the given value of the parameter is

[tex]y - 0 = pi(x + pi)[/tex]

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