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Consider the following function. f(2) = 14, f '(2) = 6.6; x = 2.5 (a) write a linearization for f with respect to x. fl(x) = (b) use the linearization to estimate f at the given input. fl(2.5) =

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okpalawalter8

The value of F at f(2.5) is  mathematically given as

f(2.5) =17.3

What is the value of F at f(2.5)?

Generally, the equation for  F(2) is  mathematically given as

f(2)=14  f'(2)=6.6  x=2.5

(y-y1) = m(x-x1)

y-14) = 6.6(x-2)

y-14 =6.6x-13.2

y =6.6x+0.8

Therefore

f(x)=6.6x+0.8

then

f(2.5) =6.6(2.5)+0.8

f(2.5) =17.3

In conclusion, The value of F at f(2.5) is  

f(2.5) =17.3

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