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Provide the missing organic structures. Include stereochemistry where appropriate. Do not draw inorganic by-products.
Part 1) Draw structure A and include all four bonds at chiral centers.
Part 2) Draw structure B.
Part 3) Draw structure C.

Provide the missing organic structures Include stereochemistry where appropriate Do not draw inorganic byproducts Part 1 Draw structure A and include all four b class=

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Answer:

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Explanation:

Part 1) Structure A is the product that results from a halogenation reaction (aka. bromination reaction). This reaction is a specific type of addition reaction. In this reaction, the double bond is broken when two bromine atoms are added to the affected carbons. There are two chiral centers in the product.

Part 2) Structure B is the product that results from a dehydrohalogenation reaction. In the first part of this reaction, a hydrogen from one chiral center and a bromine from the other are removed and replaced by a pi bond (resulting in an alkene) Since there are two equivalents of NaNH₂, this process repeats itself (resulting in an alkyne).

Part 3) Structure C is the product that results from a catalytic hydrogenation reaction. In this reaction, one hydrogen is added to each affected carbon. Lindlar's Catalyst reduces the alkyne to an alkene.

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