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A wire is moving perpendicularly through a magnetic field of strength 0.100 t with speed 60.0 m/s. if the potential difference between the ends of the wire is 8.00 v, what is the length of the wire?

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tushargupta0691

The motional emf induced in the wire is expressed as L ≈ 0.833 m

Given Data

• Magnetic field, B =0.100 TB =0.100 T

• Speed of the wire (perpendicular to the magnetic field), v =60.0 m/s

• Potential difference between the ends of the wire, E = 5.00 V

Finding the length (L) of the wire

The motional emf induced in the wire is expressed as

E =B×L×V

5.00 V =0.100 T×L×60.0 m/s

L ≈0.833 m

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