Answer:
d = 45t
Step-by-step explanation:
Define the variables:
[tex]\large \boxed{\sf Distance=speed \times time}[/tex]
Therefore, if the train traveled at a constant speed (k) then:
[tex]\boxed{d = kt}[/tex]
where k is some constant to be found.
Given:
Substitute the given values into the formula and solve for k:
[tex]\begin{aligned}d & = kt \\\implies 67.5 & = 1.5k \\k & = \dfrac{67.5}{1.5} \\k & = 45\end{aligned}[/tex]
Substitute the found value of k into the equation thus creating an equation that shows a proportional relationship:
[tex]\large \boxed{d=45t}[/tex]