Respuesta :
A 24.1ml agno3 solution reacts with excess potassium chloride solution to yield 1.16g of AgCl precipitate. The molarity of silver ion is 0.035 M
The rection of Silver Nitrate and Potassium Chloride:
AgNO₃ (aq) + 2KCl (aq) ⇄ AgCl (s) + 2KNO₃ (aq)
Where, Silver Nitrate is a aqueous solution,
Potassium Chloride is a aqueous solution,
Silver chloride is a solid solution, and
Potassium nitrate is a aqueous solution.
Hence, Let's now find the Molarity of Ag⁺ to get the Ag ion,
∴ Molarity of Ag⁺ is:
[tex]\frac{(1.16 g of AgCl)(\frac{1 mol of AgCl}{143.32 g of AgCl} )(\frac{1 mol of Ag+}{1 mol of AgCl} )} {(24.1 ml) (\frac{1 L}{1000 ml} )}[/tex]
⇒ Molarity of Ag⁺ = 0.035 M Ag⁺
Hence, The Molarity of silver ion is 0.035 M
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