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Please help i dont understand how to do this, and if you answer please show your work for it
Calculate the mass of (the ^ means exponent)
7.06 x 10^23 He atoms
1.07 x 10^23 Mg atoms
4.06 x 10^22 molecules of O2
8.19 x 10^24 molecules CO

Calculate the volume of
2800 g of C6H1206
45 moles of H2O
9.2 grams of Fe
2.8 x 10^26 particles of Al2O3
5.6 moles of H2SO3

Respuesta :

The Avogadro's number is used to obtain the required results as;

1) 4.69 g

2) 4.26 g

3) 2.158 g

4) 381 g

5) 348.5 L

6)  1008 L

7) 3.6 L

8) 4.7 * 10^4 g

9) 112 L

What is the Avogadro’s number?

The Avogadro’s number could be used to deduce the amount of substance. Let us recall that in the theory of Professor Avogadro, the mole is the number of elementary entities of a substance. In this case these elementary entities is a reference to the atoms, molecules and ions that could be found in the substance. With that in mind, we shall now carry out the calculations.

1)  6.02 * 10^23 atoms of helium has a mass of 4g

7.06 x 10^23  He atoms of He has a mass of 4.69 g

2) 6.02 * 10^23 atoms of Mg has a mass of 24 g

1.07 x 10^23 Mg atoms has a mass of 4.26 g

3) 6.02 * 10^23 molecules of O2 has a mass of 32 g/mol

4.06 x 10^22 molecules of O2 has a mass of 2.158 g

4) 6.02 * 10^23 molecules of CO has a mass of 28 g

8.19 x 10^24 molecules CO has a mass of 381 g

5) Number of moles = 2800g/180 g/mol = 15.56 moles

Given that 1 mole occupies 22.4 L

15.56 moles occupies 348.5 L

6) Given that 1 mole occupies 22.4 L

45 moles occupies 1008 L

7) Number of moles of Fe = 9.2 g/56 = 0.16 moles

Given that 1 mole occupies 22.4 L

0.16 moles occupies 3.6 L

8) 6.02 * 10^23 particles have a mass of 102 g

2.8 x 10^26 particles have a mass of 4.7 * 10^4 g

9) Given that 1 mole occupies 22.4 L

5 moles of the acid occupies 112 L

Learn more about Avogadro’s number:https://brainly.com/question/11907018

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