The median and mode of the data set is
This is further explained below.
Generally, median = value of [tex]$\left(\frac{n+1}{2}\right)^{\text {th }}$[/tex] the position
- the value of [tex]$\left(\frac{20+1}{2}\right)^{\text {th }}$[/tex] the position
= value of the position
= value of [tex]$10^{\text {th }}$[/tex] position +0.5 (value of 10^th position - value of 9th position)
Arranging the data below.
8,10,13,15,15,15,15,15,16,16,16$, $17,18,19,20,20,21,29,28,30
median =16+0.5(16-16)
median =16
mode = { value of maximum frequency }
mode =15
Read more about frequency
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The data set represents the number of students per faculty member for 20 public colleges 13 15 15 8 16 20 28 19 18 15 21 23 30 17 10 16 15 16 2[tex]$(10.5)^{\text {th }}$[/tex]0 15. Use five classes.
What is the median and mode of the data
