The next point to be graphed after graphing the y-intercept since the slope is negative and the graph cuts of at; (0, -10) is; (-5, 5).
What is the next point to be graphed apart from the y-intercept since the graph cuts off at (0, -10)?
According to the task content; it follows that the next point to be graphed apart from the given y-intercept is to be determined.
It follows from comparison with the slope-intercept form of a linear equation;
y = mx+c that the slope of the given equation is; -3.
Hence, considering the point, x = -5, the value of y is;
y = -3(-5) -10
y = 15 - 10
y = 5.
Therefore, the required coordinate to be graphed is; (-5, 5).
Ultimately, the next point to be graphed after graphing the y-intercept since the slope is negative and the graph cuts of at; (0, -10) is;
(-5, 5).
Read more on graphing linear equations;
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