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The admission fee at an amusement park is $ 3.00 for children and $ 7.00 for adults. On a certain day, 297 people entered the park, and the admission fees collected totaled $ 1551 . How many children and how many adults were admitted?
There were _________________ children admitted.
There were _________________ adults admitted

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Answer:

There were 132 children admitted.

There were 165 adults admitted.

Step-by-step explanation:

Given information:

  • Child admission fee = $3.00
  • Adult admission fee = $7.00
  • Total admissions = 297 people
  • Total admission fees collected = $1,551

Define the variables:

  • Let x = number of children admitted to the park.
  • Let y = number of adults admitted to the park.

Create two equations from the given information and defined variables:

[tex]\textsf{Equation 1}: \quad x+y=297[/tex]

[tex]\textsf{Equation 2}: \quad 3x+7y=1551[/tex]

Solve the first equation for y:

[tex]\implies x+y=297[/tex]

[tex]\implies x+y-x=297-x[/tex]

[tex]\implies y=297-x[/tex]

Substitute the found expression for x into the second equation and solve for y:

[tex]\implies 3x+7y=1551[/tex]

[tex]\implies 3x+7(297-x)=1551[/tex]

[tex]\implies 3x+2079-7x=1551[/tex]

[tex]\implies 2079-4x=1551[/tex]

[tex]\implies 2079-1551-4x=1551-1551[/tex]

[tex]\implies 528-4x=0[/tex]

[tex]\implies 528-4x+4x=0 + 4x[/tex]

[tex]\implies 528= 4x[/tex]

[tex]\implies \dfrac{528}{4}= \dfrac{4x}{4}[/tex]

[tex]\implies x=132[/tex]

Substitute the found value of x into the expression for y and solve for y:

[tex]\implies y=297-x[/tex]

[tex]\implies y=297-132[/tex]

[tex]\implies y=165[/tex]

Therefore:

  • There were 132 children admitted.
  • There were 165 adults admitted.