Two factory plants are making TV panels. Yesterday, Plant A produced 6000 fewer panels than Plant B did. Five percent of the panels from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 1410 defective panels?

Respuesta :

Plant P produced 15333 numbers of panels when the two plants together produced 1410 defective panels using unitary method.

What is unitary method?

It is a method for figuring out a single unit's value, then multiplying that value by itself to get the required value.

Given data

Plant produces defective panels = 1140

Plant A produce = 5%

Plant B produce = 4%

Assume,

Number panels Plant B produce = x

Number panels Plant A produce = x - 6000

[tex]\frac{5}{100}[/tex](x) + [tex]\frac{4}{100}[/tex](x-6000) = 1140

0.05x + 0.04x - 240 = 1140

0.09x = 1380

x = 15333

Plant P produced 15333 numbers of panels when the two plants together produced 1410 defective panels using unitary method.

To learn more about unitary method, visit

https://brainly.com/question/17355857

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