Answer: 48, 29, 10, -9, -28
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Explanation:
The first term is 48 because of the notation f(1) = 48
To get the second term, we subtract 19 from 48
f(n) = previous - 19
f(2) = f(1) - 19
f(2) = 48 - 19
f(2) = 29
Then repeat the same idea for the third term
f(n) = previous - 19
f(3) = f(2) - 19
f(3) = 29- 19
f(3) = 10
The process keeps going until you have five terms as listed in bold above.
It is an arithmetic sequence with first term 48 and common difference -19.
