Answer: The final velocity will be 30 m/s
Explanation:
[tex]v_{i} = 10 m/s\\a = 2.0m/s^{2} \\t = 10s\\v_{f} = ?\\\\a = \frac{v_{f} - v_{i}}{t} \\2.0 = \frac{v_{f} - 10}{10} \\20 = v_{f} - 10\\v_{f} = 30[/tex]
Answer:
30 m/s
Explanation:
[tex]\boxed{\begin{array}{c} \text{\underline{The Constant Acceleration Equations (SUVAT)}}\\\\\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}}[/tex]
[tex]\boxed{\begin{minipage}{9 cm}s = displacement in m (meters)\\u = initial velocity in m/s (meters per second)\\v = final velocity in m/s (meters per second)\\a = acceleration in m/s$^{2}$ (meters per second per second)\\t = time in s (seconds)\\\\When using SUVAT, assume the object is modeled\\ as a particle and that acceleration is constant.\end{minipage}}[/tex]
Given:
Substitute the given values into v = u + at and solve for v:
[tex]\begin{aligned}v & = u+at\\\implies v & = 10 + 2(10)\\& = 10 + 20\\& = 30\; \sf m/s\end{aligned}[/tex]
Therefore, the final velocity of the vehicle is 30 m/s.
