The partial pressure of oxygen in such conditions is equal to 160 mm Hg.
As the percentage of oxygen in the air is 21 percent, the mole fraction of oxygen in the air can be calculated as follows;
mole fraction of oxygen in air = 21 ÷ 100 = 0.21
Now we can determine the partial pressure of oxygen by using the equation given by Raoult's law as follows;
partial pressure of oxygen = total pressure of air × mole fraction of oxygen
As the atmospheric pressure at sea level is stated to be 760 mm hg and the calculated value of the mole fraction of oxygen is 0.21, substituting these values in the equation as follows;
partial pressure of oxygen = 760 mm hg × 0.21
partial pressure of oxygen = 160 mm hg
Therefore, the partial pressure of oxygen is calculated to be 160 mm hg.
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