the volume vv of an ideal gas varies directly with the temperature tt and inversely with the pressure pp . a cylinder contains oxygen at a temperature of 310310 degrees k and a pressure of 1818 atmospheres in a volume of 120120 liters. find the pressure if the volume is decreased to 9595 liters and the temperature is increased to 320320 degrees k.

Respuesta :

The final pressure of the ideal gas is 23.47 atm.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

V1 = 120 L

P1 = 18 atm

T1 = 310 K

V2 = 95 L

T2 = 320 K

When the initial and final gas is the same, we can use the ratio of the ideal gas as

(P2 . V2) / (P1 . V1) = T2 / T1

(P2 . 95) / (18 . 120) = 320 / 310

P2 = 23.47 atm

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