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63.8 g of manganese(ii)sulfate monohydrate is heated in an oven until all the water is driven off. what is the mass of the anhydrous compound? provide your answer in decimal notation rounded to the appropriate number of significant figures.

Respuesta :

The mass of anhydrous compound in 63.8 grams of manganese(ii)sulfate monohydrate is 57.01 grams.

As per the known fact, mass of manganese(ii)sulfate monohydrate is 169.02 grams/mole. Also, the mass of monohydrate which is one molecule of water is 18 grams/mole. So, the percentage of water in manganese(ii)sulfate monohydrate is 18/169.02×100

Percentage = 10.6%

Now, the amount of water in 63.8 grams of manganese(ii)sulfate monohydrate is : 10.6%×63.8

Calculating percentage

Amount of water = 6.79 grams

Mass of anhydrous compound = 63.8 - 6.79

Performing subtraction on Right Hand Side

Mass of anhydrous compound = 57.01 grams

Thus, 57.01 grams is present in mentioned salt.

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