The concentration on diluting the solution by student is 1 M.
The concentration and volume are related to each other as - [tex] M_{1}[/tex] [tex] V_{1}[/tex] = [tex] M_{2}[/tex] [tex] V_{2}[/tex], where [tex] M_{1}[/tex] and [tex] M_{2}[/tex] are initial and final molarity and [tex] V_{1}[/tex] and [tex] V_{2}[/tex] are initial and final volume.
[tex] M_{1}[/tex] is 10.1 M, [tex] V_{1}[/tex] is 12.4 ml, [tex] M_{2}[/tex] is to be calculated and [tex] V_{2}[/tex] is 125 ml. Keep the values in formula to find the value of [tex] M_{2}[/tex].
10.1×12.4 = [tex] M_{2}[/tex]×125
[tex] M_{2}[/tex] = 125.24 ÷ 125
Performing division
[tex] M_{2}[/tex] = 1.00192 M or 1 M.
Thus, the concentration of diluted solution is 1 M.
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