Answer:
[tex]y-8=-\dfrac{6}{5}(x-5)[/tex]
Step-by-step explanation:
Define the given points:
First find the slope of the line by substituting the given points into the slope formula:
[tex]\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{2-8}{10-5}=-\dfrac{6}{5}[/tex]
To find the equation in point-slope form, simply substitute the found slope and one of the given points into the point-slope formula:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-8=-\dfrac{6}{5}(x-5)[/tex]