(b) Construct a 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone. Round the answers to at least three decimal places.
A 90% confidence interval for the proportion of cell phone owners aged 18 - 24
who have an Android phone is

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b Construct a 90 confidence interval for the proportion of cell phone owners aged 18 24 who have an Android phone Round the answers to at least three decimal pl class=

Respuesta :

A 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone is 0.503 < p < 0.397.

In the given question,

We have to construct a 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone.

A 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone is

..............< p <...............

We have to construct the 90% confidence interval.

From the given question we know that among 240 cell phone owners aged 18 - 24 surveyed, 108 said their phone was an android phone.

So the total number of cell phone owners aged 18 - 24 is 240.

So n=240

From them 108 have an android phone.

So x=108

Estimation of sample proportion([tex]\hat p[/tex]) = x/n

Now putting the value

Estimation of sample proportion([tex]\hat p[/tex]) = 108/240

Estimation of sample proportion([tex]\hat p[/tex]) = 0.45

Now the construct a 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone

C.I. = [tex](\hat p \pm z_{\alpha /2}\sqrt\frac{\hat p(1-\hat p)}{n}})[/tex]

As we know that

[tex]\hat p=0.45[/tex]

Now finding the value of [tex]z_{\alpha /2}[/tex]

We have to find the 90% confidence interval. We can write 90% as 90/100 = 0.90

So [tex]\alpha[/tex] = 1-0.90

So [tex]z_{\alpha /2}=z_{0.10 /2}[/tex]

[tex]z_{\alpha /2}=z_{0.05}[/tex]

From the standard z table

[tex]z_{0.05}[/tex] = 1.645

Now putting the value in the

C.I. =  [tex](\hat p \pm z_{\alpha /2}\sqrt\frac{\hat p(1-\hat p)}{n}})[/tex]

C.I. = [tex](0.45 \pm 1.645{\sqrt\frac{0.45(1-0.45)}{240}})[/tex]

Simplifying

C.I. = [tex](0.45 \pm 1.645{\sqrt\frac{0.45\times0.55}{240}})[/tex]

C.I. = [tex](0.45 \pm 1.645{\sqrt\frac{0.2475}{240}})[/tex]

C.I. = [tex](0.45 \pm 1.645\sqrt{0.001031})[/tex]

C.I. = [tex](0.45 \pm 1.645\times0.0321)[/tex]

C.I. = [tex](0.45 \pm 0.053)[/tex]

We can write it as

C.I. = {(0.45+0.053),(0.45-0.053)}

C.I. = (0.503,0.397)

Hence, a 90% confidence interval for the proportion of cell phone owners aged 18 - 24 who have an Android phone is

0.503 < p < 0.397.

To learn more about confidence interval link is here

https://brainly.com/question/24131141

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