question 26 options: a (very small) computer for embedded applications is designed to have a maximum main memory of 8,192 cells. each cell holds 16 bits. how many address bits does the memory address register of this computer need?

Respuesta :

13 address bits are needed for the main memory of 8192 cells.

How to calculate the address bits?

Step 1 is to determine the address's bit length (n bits)

Step 2: Determine how many memory locations there are (bits)

To calculate the address bits we need to know which power of the cells is raised to 2. so 13 address bits because 2 ^ 13 = 8192 cells

What are the address bits?

An index in memory is the main storage address. The address of a single byte is a 32-bit address. An address can be found on 32 of the bus's wires (there are many more bus wires for timing and control). Addresses like 0x2000, which appear to be a 16-bit pattern, are occasionally brought up in conversation.

Hence 13 address bits are needed for the main memory

To know more about address bits please follow the link

https://brainly.com/question/13267271

#SPJ4