Respuesta :
Solution:
Given:
[tex]\begin{gathered} y=3x-2 \\ \text{Through the point (2,11)} \end{gathered}[/tex]Two parallel lines have identical slopes.
[tex]m_1=m_2[/tex]Hence, the slope of line 1 is gotten by comparing the equation given to the equation of a line in the slope-intercept form.
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]
Thus,
[tex]\begin{gathered} y=mx+b \\ y=3x-2 \\ \\ \text{Comparing both equations,} \\ m_1=3 \\ \text{The slope of line 1 is 3.} \end{gathered}[/tex]Since both lines are parallel, then the slopes are equal.
[tex]\begin{gathered} m_1=m_2=3 \\ m_2=3 \\ \text{The slope of line 2 is 3} \end{gathered}[/tex]To get the equation of line 2 through the point (2,11), the formula below is used;
[tex]\begin{gathered} \frac{y-y_1}{x-x_1}=m \\ \\ \text{where;} \\ x_1=2 \\ y_1=11 \\ m=3 \\ \text{Hence,} \\ \frac{y-11}{x-2}=3 \\ \text{Cross multiplying,} \\ y-11=3(x-2) \\ y-11=3x-6 \\ y=3x-6+11 \\ y=3x+5 \end{gathered}[/tex]
Therefore, the equation of the line that is parallel to y = 3x - 2 passing through the point (2,11) is;
[tex]y=3x+5[/tex]