Respuesta :
SOLUTION
Write out the given point
[tex]\begin{gathered} (4,3) \\ \text{and } \\ (8,0) \end{gathered}[/tex]The equation of the line passing through the point above will be obtain by following the steps
Step1: Obtain the slope of the line
[tex]\begin{gathered} \text{slope,m}=\frac{y_2-y_1}{x_2-x_1} \\ \text{Hence } \\ x_1=4,x_2=8 \\ y_1=3,y_2=0 \end{gathered}[/tex]Substituting the values we have
[tex]\begin{gathered} \text{slope,m}=\frac{0-3}{8-4}=-\frac{3}{4} \\ \text{Hence } \\ m=-\frac{3}{4} \end{gathered}[/tex]Step 2: Obtain the y- intercept
The y-intercept is the point where the graph touch the y, axis
[tex]\begin{gathered} \text{slope, m=-3/4} \\ y=6 \\ y-intercept=6 \end{gathered}[/tex]Steps 3; use the slope intercept rule
[tex]\begin{gathered} y=mx+b \\ \text{Where m=-3/4,b=y-intercept} \\ \text{Then } \\ y=-\frac{3}{4}x+6 \end{gathered}[/tex]Hence
The equation in slope intercept form is
y = - 3/4 x + 6
