Given:
[tex]f(x)=x^2-1\text{ ; g(x)=x-2 }[/tex][tex](\frac{f}{g})(t+2)=\frac{f(t+2)}{g(t+2)}[/tex][tex](\frac{f}{g})(t+2)=\frac{(t+2)^2-1}{(t+2)^{}-2}[/tex][tex](\frac{f}{g})(t+2)=\frac{t^2+4t+4-1}{t+2-2}[/tex][tex](\frac{f}{g})(t+2)=\frac{t^2+4t+3}{t}[/tex][tex](\frac{f}{g})(t+2)=\frac{(t+1)(t+3)}{t}[/tex]
