Respuesta :
Answer
77.0 grams of CO are produced when 33.0 g of C reacts.
Explanation
Given:
Mass of C = 33.0 g
Equation: Fe₂O₃(s) + 3C(s) → 2Fe(s) + 3CO(g)
What to find;
The grams of CO that are produced when 33.0 g of C reacts.
Step-by-step solution:
Step 1: Convert 33.0 g of C to moles.
Using the formula for moles and the molar mass of C = 12.0 g/mol, the moles of C is
[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles\text{ }of\text{ }C=\frac{33.0\text{ }g}{12.0\text{ }g\text{/}mol}=2.75\text{ }mol \end{gathered}[/tex]Step 2: Determine the moles of CO produced.
Using the mole ratio of C and CO from the balance equation and the moles of C in step 1; the moles of CO produced is calculated as follows:
[tex]\begin{gathered} 3\text{ }mol\text{ }C=3\text{ }mol\text{ }CO \\ \\ 2.75\text{ }mol\text{ }C=x \\ \\ x=\frac{2.75\text{ }mol\text{ }C}{3\text{ }mol\text{ }C}\times3\text{ }mol\text{ }CO \\ \\ x=2.75\text{ }mol\text{ }CO \end{gathered}[/tex]Step 3: Convert the moles of CO produced to mass in grams.
The moles of CO produced in step above can be converted to mass in grams as shown below
[tex]\begin{gathered} Mass=Moles\times Molar\text{ }mass \\ \\ Molar\text{ }mass\text{ }of\text{ }CO=12.0+16.0=28.0\text{ }g\text{ /}mol \\ \\ Mass\text{ }of\text{ }CO\text{ }produced=2.75\text{ }mol\times28.0\text{ }g\text{/}mol \\ \\ Mass\text{ }of\text{ }CO\text{ }produced=77.0\text{ }g \end{gathered}[/tex]Hence, 77.0 grams of CO are produced when 33.0 g of C reacts.
