Answer:
Given to solve,
[tex]\lim _{x\to-1}(2x+2)(x+2)[/tex]
From the rules for limits, we can see that for any polynomial, the limit of the polynomial when x approaches a point k is equal to the value of the polynomial at k.
The given function of the limit is a quadratic function, the limit of the quadratic equation when x approaches a point -1 is equal to the value of the quadratic equation at -1.
we get,
[tex]\lim _{x\to-1}(2x+2)(x+2)=(2(-1)+2)((-1)+2)[/tex][tex]=(-2+2)(1)=0[/tex]
[tex]\lim _{x\to-1}(2x+2)(x+2)=0[/tex]
Answer is : 0
