Explanation
[tex]\frac{4}{n+2}=\frac{7}{n}[/tex]we need to solve for n
Step 1
cross multiply
[tex]\begin{gathered} \frac{4}{n+2}=\frac{7}{n} \\ 4\cdot n=7(n+2) \\ 4n=7n+14 \\ \end{gathered}[/tex]Step 2
subtract 4n in both sides
[tex]\begin{gathered} 4n=7n+14 \\ 4n-4n=7n+14-4n \\ 0=3n+14 \end{gathered}[/tex]Step 3
subtract 14 in both sides,
[tex]\begin{gathered} 0=3n+14 \\ 0-14=3n+14-14 \\ -14=3n \end{gathered}[/tex]Step 4
Finally, divide both sides by 3
[tex]\begin{gathered} \frac{-14}{3}=\frac{3n}{3} \\ n=-\frac{14}{3} \end{gathered}[/tex]I hope this helps you
