Hello! First, let's remember:
We can write a point as a cartesian coordinate (x, y).
The exercise has given two points, A(4,3) and B(8,1).
a. Slope:
To calculate the slope of a line, we can use the formula below:
[tex]\text{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
Let's consider A equal to the first point (4, 3) = (x1, y1), and B will be the second point (8, 1) = (x2, y2). Replacing these values in the formula:
[tex]\text{Slope}=\frac{1_{}-(3)_{}}{8-(4)}=\frac{-2}{4}=-\frac{1}{2}[/tex]
b. Lenght of segment AB:
To find this length, we have to use another formula. Now we will calculate the distance between two points:
[tex]\text{Distance}=\sqrt[]{(x_2-x_1)^2+(y_2_{}-y_1_{})^2}[/tex]
Still considering A (4, 3) = (x1, y1), and B (8, 1) = (x2, y2), let's replace the values in the formula:
[tex]\begin{gathered} \text{Distance}=\sqrt[]{(8_{}-4_{})^2+(1-3_{})^2} \\ \text{Distance}=\sqrt[]{(4_{})^2+(-2_{})^2} \\ \text{Distance}=\sqrt[]{(16^{}+4)^{}} \\ \text{Distance}=\sqrt[]{20} \\ \text{Distance}=2\sqrt[]{5} \end{gathered}[/tex]
c. Midpoint of segment AB:
This value will be the medium point. To calculate it, we'll use another formula:
[tex]x_m=(\frac{x_1+x_2}{2}+\frac{y_1+y_2_{}_{}}{2})[/tex]
Still considering the same values for (x1, y1) and (x2, y2), let's replace them:
[tex]\begin{gathered} x_m=(\frac{8+4_{}}{2},\frac{3+1_{}}{2}) \\ \\ x_m=(\frac{12_{}}{2},\frac{4_{}}{2}) \\ \\ x_m=(6,2) \end{gathered}[/tex]
The midpoint of segment AB will be at point X (6, 2).
You can see this line represented in a cartesian plan below:
