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There are two boxes containing only red and purple pens.Box A has 12 purple pens and 3 red pens.Box B has 14 purple pens and 6 red pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a purple or red pen from Box A.Event 2: choosing a green pen from Box B.Event 3: choosing a purple pen from Box B.Event 4: choosing a purple pen from Box A.Least likelyMost likelyEventEventEventEvent

There are two boxes containing only red and purple pensBox A has 12 purple pens and 3 red pensBox B has 14 purple pens and 6 red pensA pen is randomly chosen fr class=

Respuesta :

Event 1: choosing a purple or red pen from Box A

All pens are purple or red so the probability is:

[tex]P=\frac{12+3}{15}=\frac{15}{15}=1[/tex]

Event 2: choosing a green pen from Box B

We don't have green pens, so the probability is 0.

Event 3: choosing a purple pen from Box B

We have 14 purple pens and 20 total pens, so:

[tex]P=\frac{14}{20}=\frac{7}{10}=0.7[/tex]

Event 4: choosing a purple pen from Box A

We have 12 purple pens and 15 total pens, therefore:

[tex]P=\frac{12}{15}=\frac{4}{5}=0.8[/tex]

Listing from least likely to most likely, we have:

event 2 < event 3 < event 4 < event 1

Answer:

Event 2, Event 3, Event 4, Event 1

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