Respuesta :

[tex]\begin{gathered} x_1=\frac{-9+\sqrt{17}}{2} \\ x_2=\frac{-9-\sqrt{17}}{2} \end{gathered}[/tex]

Explanation

[tex]2x^2-3x-1=0[/tex]

Step 1

remember the quadratic formula.

if you have the equation

[tex]ax^2+bx+c=0[/tex]

the value for x is

[tex]x=\frac{-b^2+\sqrt{b^2}-4ac}{2a}[/tex]

Step 2

let

[tex]ax^2+bx+c=2x^2-3x-1[/tex]

a=2

b=-3

c=-1

Step 3

replace

[tex]undefined[/tex]

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