Solution:
Given the expression below
[tex](^8_3)[/tex]
Applying the combination formula below
[tex]^nC_r=\frac{n!}{r!(n-1)!}[/tex]
The binomial coefficient will be
[tex]=\frac{8!}{3!(8-3)!}=\frac{8!}{3!5!}=\frac{8\times7\times6\times5\times4\times3\times2\times1}{3\times2\times1\times5\times4\times3\times2\times1}=56[/tex]
Hence, the answer is 56
