Statement Problem: Verify the identity;
[tex]\frac{\sin^2t}{\cos t}=\sin t\tan t[/tex]
Solution:
We can re-express the equation as;
[tex]\frac{\sin^2t}{\cos t}=\frac{\sin t\sin t}{\cos t}[/tex]
Then;
[tex]\frac{\sin^2t}{\cos t}=\sin t\sin t(\frac{1}{\cos t})[/tex]
Recall that;
[tex]\frac{\sin t}{\cos t}=\tan t[/tex]
Thus;
[tex]\frac{\sin^2t}{\cos t}=\sin t\tan t[/tex]
CORRECT OPTION: B
