In a scale drawing of a rectangularswimming pool, the scale is 2 inch: 4feet. Find the perimeter and area ofthe swimming pool.15 in.3.5 in.

The given scale is
[tex]2in\colon4ft[/tex]This means each two inches of the scale represents 4 feet of the actual size (or each inch is equivalent to two feet).
So, if the dimensions of the scale are 15 inches by 3.5 inches, then the actual dimensions would be 30 feet by 7 feet.
The perimeter would be
[tex]P=2(w+l)=2(30+7)=2(37)=74ft[/tex]The area would be
[tex]A=w\cdot l=30.7=210ft^2[/tex]