Given:
It is given that you roll a die 96 times.
Required:
We have to find the expectation of landing on 3 or 4.
Explanation:
If you roll a die then there are 6 possibilities (1-6) and the possibility of landing on 3 or 4 is 2.
Then the probability of landing on 3 or 4 is
[tex]\frac{2}{6}=\frac{1}{3}[/tex]If you roll the die 96 times then the probability of landing 3 or 4 is
[tex]\frac{1}{3}\times96=32[/tex]Final answer:
Hence the final answer is:
You could expect it to land on 3 or 4 is
[tex]32[/tex]