Volume of the cone = 50.29 mm³
Explanation:[tex]\text{Volume = 1/3}\pi r^2\text{ h}[/tex]radius = r = ?
height = 3mm
slant height = 5mm
To get the radius, we would apply pythagoras' theorem:
Hypotenuse² = opposite² + adjacent²
hypotenuse = 5mm
opposite = 3mm
adjacent = radius = ?
5² = 3² + radius²
25 = 9 + radius²
25 - 9 = radius²
16 = radius²
radius = √16
radius = 4
[tex]\text{Volume of the cone = }\frac{1}{3}\times\frac{22}{7}\times4^2\times3[/tex][tex]\text{Volume of the cone = }50.29mm^3[/tex]