Given:
Length of the two adjacent sides = 533 feet and 525 feet
Angle between the two sides = 53 degrees
Let's find the area of park.
Let's make a sketch representing this situation:
Let's first find the length of the third side.
Apply the cosine rule.
We have:
[tex]\begin{gathered} a=\sqrt{533^2+525^2-2(533)(525)cos53} \\ \\ a=\sqrt{284089+275625-336805.7777} \\ \\ a=\sqrt{222908.2223} \\ \\ a=472.13\text{ ft} \end{gathered}[/tex]
Now, apply the Heron's formula to find the area:
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]
Where:
a = 472.13
b = 533
c = 525
Let's solve for s:
[tex]\begin{gathered} s=\frac{472.13+533+525}{2} \\ \\ s=\frac{1530.13}{2} \\ \\ s=765.1\text{ } \end{gathered}[/tex]
• Therefore, the area will be:
[tex]\begin{gathered} A=\sqrt{765.1(765.1-472.13)(765.2-533)(765.1-525)} \\ \\ A=\sqrt{765.1(292.97)(232.1)(240.1)} \\ \\ A=111738.81\text{ ft}^2 \end{gathered}[/tex]
The area in square feet is 111,738.81 square feet.
Now, let's find the area in square yards.
Apply the metrics of measurement.
Where:
1 square yard = 9 square feet
Thus, we have:
111,738.81 square feet =
[tex]\frac{111738.81}{9}=12415.4\approx12415\text{ square yards}[/tex]
Therefore, the area of the park in square yards is 12,415 square yards.
ANSWER:
12,415 square yards.
