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The period T(In seconds) of a pendulum is given by T=2PI(Square root of L/32) Where L stands for length (in feet) of the pendulum If pi =3.14 and the period is 6.28 what is the length

The period TIn seconds of a pendulum is given by T2PISquare root of L32 Where L stands for length in feet of the pendulum If pi 314 and the period is 628 what i class=

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Let me check your question

[tex]T\text{ = 2}\cdot\text{ 3.14}\cdot\text{ }\sqrt[]{L/\text{ 32}}[/tex]

[tex]\frac{T}{2\cdot\text{ 3.14}}\text{ = }\sqrt[]{L/\text{ 32}}[/tex]

T= the period = 6.28

[tex]\frac{6.28}{6.28}\text{ = }\sqrt[]{L/\text{ 32}}[/tex]

[tex]L/32=1^2[/tex]

[tex]L=32[/tex]

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Answer

L= 32

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