Let price of 1 soup be "x" and 1 stew be "y".
4 soup and 4 stew is $31, thus we can write:
[tex]4x+4y=31[/tex]Also, given
2 soup and 1 stew costs $12.25, thus we can write:
[tex]2x+y=12.25[/tex]Let' solve this for y and substitute it back to Equation 1. Then we will solve for x. The process is shown below:
[tex]y=12.25-2x[/tex]Substituting,
[tex]\begin{gathered} 4x+4y=31 \\ 4x+4(12.25-2x)=31 \\ 4x+49-8x=31 \\ 49-31=8x-4x \\ 18=4x \\ x=\frac{18}{4} \\ x=4.5 \end{gathered}[/tex]Finding y:
[tex]\begin{gathered} y=12.25-2x \\ y=12.25-2(4.5) \\ y=3.25 \end{gathered}[/tex]Thus,
Answer:
Each order of Soup = $4.50
Each order of Stew = $3.25
