Solve for the triangle where there is a question mark!

SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Label the right-angled triangle
STEP 2: Write the trigonometry ratios
[tex]\begin{gathered} \sin \theta=\frac{\text{opposite}}{\text{hypotenuse}} \\ \cos \theta=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \end{gathered}[/tex]STEP 3: Write the given values to decide which ratio to use
Let the part with the question be represented by m
[tex]\begin{gathered} \text{adjacent}=7,\text{hypotenuse}=12,m=\text{?} \\ U\sin g\text{ the cos ratio from step 2;} \\ \cos m=\frac{7}{12} \\ m=\cos ^{-1}(\frac{7}{12})=\cos ^{-1}0.5833333333 \\ m=54.31466529 \\ m\approx54.31 \end{gathered}[/tex]Therefore, the value of mising angle labelled m is approximately 54.31 degrees