We are given the following the following inequality:
|x - 5| >= 1
When we have a inequality in the format:
|f(x)| >= a
There are two possible solutions.
Either f(x) <= -a or f(x) >= a
In this question:
|x - 5| >= 1
x - 5 <= -1
x <= -1 + 5
x <= 4
Or
x - 5 >= 1
x >= 1 + 5
x >= 6
In interval notation, the answer is:
[tex](-\infty,4\rbrack\cup\lbrack6,+\infty)[/tex]The solution on the number line is:
