Periodic Deposit: $? at the end of each monthRate: 7.5% compounded monthlyTime: 3 yearsFinancial Goal: $35,000O A. $2,628; $31,536 from deposits and $3,464 from interestB. $776; $27,936 from deposits and $7,064 from interestO c. $933; $33,588 from deposits and $1,412 from interestOD. $870; $31,320 from deposits and $3,680 from interest

Periodic Deposit at the end of each monthRate 75 compounded monthlyTime 3 yearsFinancial Goal 35000O A 2628 31536 from deposits and 3464 from interestB 776 2793 class=

Respuesta :

Answer:

D. $870; $31,320 from deposits and $3,680 from interest

Explanation:

In order to calculate the monthly payment, we use the formula below:

[tex]P=\frac{A\mleft(\frac{r}{n}\mright)}{\mleft[\mleft(1+\frac{r}{n}\mright)^{nt}-1\mright]}[/tex]

Given:

• The Financial Goal, A= $35,000

,

• Rate = 7.5% = 0.075

,

• Number of compounding period = 12 (Monthly)

,

• Time, t = 3 years

Substitute into the given formula:

[tex]\begin{gathered} P=\frac{35000\mleft(\frac{0.075}{12}\mright)}{\mleft[\mleft(1+\frac{0.075}{12}\mright)^{12\times3}-1\mright]} \\ P\approx\$870 \end{gathered}[/tex]

The monthly payment is $870.

[tex]\begin{gathered} \text{Total deposit}=870\times36=31,320 \\ \text{Interests}=35,000-31,320=3680 \end{gathered}[/tex]

Option D is correct.