Two figures are similar. The smaller figure has dimensions that are 3:4 the size of the largerfigure. If the area of the larger figure is 100 square units, what is the area of the smallerfigure?

Respuesta :

Answer:

56.25

Explanation:

We are told that the side lengths of the smaller figure are 3/4 the length of the larger figure.

[tex]S_{small}=\frac{3}{4}\times S_{large}[/tex]

Now since the area is proportional to the equal of the side lengths, we have

[tex]A_{small}=S_{small}^2^[/tex][tex]A_{small}=(\frac{3}{4})^2\times S_{large}^2[/tex][tex]=A_{small}=(\frac{3}{4})^2\times A_{large}^2[/tex]

The last is true since A_large = S^2_large.

Now we are told that A_large = 100 square units; therefore,

[tex]A_{small}=(\frac{3}{4})^2\times100[/tex][tex]\Rightarrow A_{small}=\frac{9}{16}\times100[/tex]

which we evaluate to get

[tex]A_{small}=\frac{9}{16}\times100=56.25[/tex][tex]\boxed{A_{small}=56.25.}[/tex]

Hence, the area of the smaller figure is 56.25.