[tex]W_{out}=F\cdot d=800\cdot40=32000[/tex][tex]P_{out}=\frac{W_{out}}{t}=\frac{32000}{20}=1600W[/tex][tex]\begin{gathered} P_{in}=\frac{W_{in}}{t}=\frac{100000}{20}=5000W \\ \end{gathered}[/tex]
Therefore:
[tex]P_{out}:P_{in}=\frac{P_{out}}{P_{in}}=\frac{1600W}{5000W}=0.32[/tex]
Answer:
1600W