Given:
Numbers in the container: All integers from 10 to 50
Let's find P(Prime numbers| numbers between 11 and 30).
Here, we are to find the conditional probability.
Apply the formula:
P(Prime|between 11 and 30) = P(prime numbers and between 11 and 30) ÷ P(numbers between 11 and 30).
Where:
• Prime numbers between 11 and 30 = 11 , 13 , 17 , 19 , 23 , 29 =6 numbers
,• Intergers from 10 to 50 = 41 integers.
To find the probability, we have:
[tex]\begin{gathered} P(Prime|between11and30)=\frac{\frac{6}{41}}{\frac{20}{41}} \\ \\ =\frac{6}{41}\ast\frac{41}{20} \\ \\ =\frac{6}{20} \\ \\ =\frac{3}{10} \end{gathered}[/tex]Therefore, we have:
P(Prime|between 11 and 30) = 3/10.
ANSWER:
D. 3/10
