where
[tex]\begin{gathered} \text{slope}=\frac{2}{5} \\ y-\text{intercept}=3 \end{gathered}[/tex]Explanation
the equation of a line in slope-intercept form is given by:
[tex]\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]Step 1
then, isolate y
[tex]-3+y=\frac{2}{5}x[/tex]i) add 3 in both sides
[tex]\begin{gathered} -3+y=\frac{2}{5}x \\ -3+y+3=\frac{2}{5}x+3 \\ y=\frac{2}{5}x+3 \end{gathered}[/tex]Hence, the answer is
[tex]y=\frac{2}{5}x+3[/tex]where
slope=2/5
y-intercept=3
I hope this helps you